Termination w.r.t. Q proof of TRS/D3311.trs

Termination w.r.t. Q of the following Term Rewriting System could be proven:

Q restricted rewrite system:
The TRS R consists of the following rules:

D(t) → 1
D(constant) → 0
D(+(x, y)) → +(D(x), D(y))
D(*(x, y)) → +(*(y, D(x)), *(x, D(y)))
D(-(x, y)) → -(D(x), D(y))
D(minus(x)) → minus(D(x))
D(div(x, y)) → -(div(D(x), y), div(*(x, D(y)), pow(y, 2)))
D(ln(x)) → div(D(x), x)
D(pow(x, y)) → +(*(*(y, pow(x, -(y, 1))), D(x)), *(*(pow(x, y), ln(x)), D(y)))

Q is empty.

↳ QTRS

  ↳ DirectTerminationProof

Q restricted rewrite system:
The TRS R consists of the following rules:

D(t) → 1
D(constant) → 0
D(+(x, y)) → +(D(x), D(y))
D(*(x, y)) → +(*(y, D(x)), *(x, D(y)))
D(-(x, y)) → -(D(x), D(y))
D(minus(x)) → minus(D(x))
D(div(x, y)) → -(div(D(x), y), div(*(x, D(y)), pow(y, 2)))
D(ln(x)) → div(D(x), x)
D(pow(x, y)) → +(*(*(y, pow(x, -(y, 1))), D(x)), *(*(pow(x, y), ln(x)), D(y)))

Q is empty.

We use [23] with the following order to prove termination.

Recursive path order with status [2].
Precedence:

D₁ > 0 > ln₁
D₁ > +₂ > ln₁
D₁ > *₂ > ln₁
D₁ > minus₁ > ln₁
D₁ > div₂ > -₂ > ln₁
D₁ > pow₂ > 1 > ln₁
D₁ > pow₂ > -₂ > ln₁
D₁ > 2 > ln₁
t > 1 > ln₁
constant > ln₁

Status:

2: multiset
D₁: multiset
0: multiset
ln₁: multiset
div₂: multiset
pow₂: multiset
*₂: multiset
minus₁: multiset
+₂: multiset
t: multiset
-₂: multiset
1: multiset
constant: multiset